two cars are traveling down the highway with the same speed if the first car increases its speed by 1km/hr and the other car decreases its speed by 10km/hr, then the first car will cover the same distance in 2hrs as the second car in 3 hrs, what is the speed of the cars

Their speed is 32 km/h.

Step-by-step explanation:

Since they're at the same speed, we can assign a variable to their speed called "x". When the first car increases its speed by 1 km/h, its new speed is "x + 1", while the other car decreases its speed by 10 km/h, so its new speed is "x - 10". The distance's formula can be expressed as below:

With the modifications to their speed, the distance the first car covers in 2 h and the distance the second car covers in 3 h is shown below:

Since the distance covered by them must be the same, we can find the value of x that makes the expressions equal.

Their speed is 32 km/h.

step-by-step explanation:

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for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.