Which complex number from the table multiplied with B from the table will result in the product 159 + 27i? A -3 − 4i
B -7 − 6i
C 13 + i
D -9 + 6i
E 8 − 8i
F -15 + 9i
G 2 + 12i
H 6 − 10i

F. -15 + 9i

Step-by-step explanation:

B = (-7 -6i)

Multiply B by F = (-15 + 9i), would give;

B × F = (-7 -6i) × (-15 + 9i)

        = -7 (-15 + 9i) - 6i (-15 + 9i)

       = 105 -63i + 90i - 54()

But = -1, so that:

105 -63i + 90i -54() = 105 -63i + 90i -54(-1)

                                  = = 105 -63i + 90i + 54

          = 159 + 27i

B × F = 159 + 27i

Thus the required complex number is F (-15 + 9i).

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this