G(t)=-(t-1)^2+5
Over which interval does g have an average rate of change of zero?

The average rate of change of is 0 in interval .

Given,

.

We have to find the interval in which have an average rate of change of zero.

We know that, the function will have average range of 0 when .

Now we calculate g(1), g(2),g(3) and g(-1),

Since,

 so the function has an average rate of zero at .

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(0, 2)

Step-by-step explanation:

The graph of g(t)= -(t-1)^2+5 is an inverted parabola with vertex at (1, 5).

Making a table of t and g values would be helpful here:

 t      g(t) = -(t - 1)^2 + 5

  2     4

  0     4

 -1      1

  1      5

We're looking for an interval on which the average rate of change is zero.

Note that this is the case on the interval (2, 4); g(0) = g(2) = 4, so the change in g is 4 - 4, or zero (0).

answer: i'm not going to give you the answer, but some hints to work it out.

step-by-step explanation: so, if there is a straight line that means that the line angle is 180°. so we subtract the 2 angle measures provided, (15 and 38) from 180. so the answer is 180 - (38 + 15). (you have to solve the equation)

im alright what do you need

step-by-step explanation: