There are 80 students in a school. Every student is taking either algebra or pre-calculus, and some students are taking both. There are 60 students in the algebra class. If 15 students are taking both algebra and pre-calculus, what is the probability that a randomly selected student is taking pre-calculus but not algebra?

1/4

Step-by-step explanation:

Total students = 80

Students taking both classes =  15

Students taking algebra class = 60

Students taking only algebra class = 60 - 15 = 45

Students taking only pre-calculus class = 80- (45+15) = 80 - 60 = 20

P( students taking pre-calculus but not algebra) = 20/80 = 1/4

three-fourths of an hour

36÷48=0.75

0.75=

what