The sum of the digits of a two-digit number is 7 .When the digits are interchanged the reversed number is five times the tens digit of the original number find the original number . frnds pls help me

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Original number is 52.

Step-by-step explanation:

1) Two digit number xy,

it can be written as 10x + y.

2) The sum of the digits of a two-digit number is 7.

x + y = 7

3) The digits are interchanged the reversed number is yx,

the new number can be written as 10y + x.

4)  The original number is 10x + y, so the tens digit of the original number  is x.

5) Five times the tens digit of the original number is 5*x.

6) The reversed number is five times the tens digit of the original number:

10y + x = 5*x

7) We have system of two equations

x + y = 7  >  x = 7 - y

10y + x = 5*x --->   10y - 4x = 0

10y - 4x = 0

10y - 4(7 - y) =0

10y - 28 + 4y = 0

14y = 28

y = 2

x = 7 - y = 7 - 2 = 5

x = 5

Original number is 52.

New number 25.

Check:

Original number is 52, the tens digit is 5.

The reversed number (25) is five times the tens digit of the original number find the original number .

25 = 5*5 True

dont think so

step-by-step explanation: