The length of a rectangle is 11 yds more than twice the width, and the area of the rectangle is 63 yd ^2, find the dimentions of the rectangle

Step-by-step explanation:

Area of a rectangle = l × w

where l is the length

w is the width

length of a rectangle is 11 yds more than twice the width is written as

l = 11 + 2w

Area = 63 yd²

(11+2w)w = 63

2w² + 11w - 63 = 0

Solve the quadratic equation

( w + 9) ( 2x - 7) = 0

w = - 9 w = 7/2 or 3.5

Since width is always positive w is 3.5 yd

l = 11 + 2(3.5)

l = 11 + 7

l = 18 yd

The length is 18 yd

The length is 18 ydThe width is 3.5 yd

Hope this helps you

you have orange juice on wednesday. (idk why this is the answer)

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i cant answer this, theres no table. sorry man

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