I NEED HELP PLEASE ASAP! :) Anne is pushing a wheelbarrow filled with mulch to place in her garden. She is pushing the wheelbarrow with a force of 70 N at an angle of 50° with the horizontal. How much work in joules is Anne doing when she pushes the wheelbarrow 25 meters? (Show work)

See below.

Step-by-step explanation:

Again, another great question!

This should be under physics, as it involves Work = Force * Distance. As Anne pushes the wheelbarrow with a force of 70 Newtons with respect to an angle of 50 degrees horizontal, the horizontal force is 70( cos 50 ). The distance over which the work is done is 25 meters, so work should be -

Work = ( 70( cos 50 ) )( 25 ),

Work = ( About ) 1124.87 Joules

The work done when Anne pushes the wheelbarrow a distance of 25 meters, is 1124.87 Joules

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x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

step-by-step explanation:

formula

x = x1 + p/w(x2 - x1)

let the line segment ab with a(x1,y1) and b(x2,y2)

a point(x,y) divide ab in the ratio, 2: 3 the x coordinate can be written as

x = x1 + p/w(x2 - x1)

here p=2 and w = 2+3

therefore,

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

similarly y coordinate y = y1 + 2/5(y2 - y1)