ABCD is a parallelogram. Given that,
DC = CE
prove that,
area of the ADE triangle is equal to the area of the parallelogram.

need explanation

plzz help!!
will give the brainliest!!

Step-by-step explanation:

We khow that ABCD is a parallelogram so its area is the product of the base (DC) and the the height

ADE is a triangle . Its area is the product of the height and the base(DE) over 2

So the triangle and the parallelogram have the same area

a4 - 3a2 - 1

step-by-step explanation:

step   1   :

equation at the end of step   1   :

  ((a4) -   3a2) -   1

step   2   :

trying to factor by splitting the middle term

2.1     factoring   a4-3a2-1  

the first term is,   a4   its coefficient is   1 .

the middle term is,   -3a2   its coefficient is   -3 .

the last term, "the constant", is   -1  

6.9

step-by-step explanation:

simple math really

6 1/2 times 0.6 = 3.9

but if you are just doing 6 and not 6 1/2 then the answer is 3.6