Samad's age and his father's age are 12 years old and 40 years old
respectively. How many years later
will Samad's father be twice as old as
Samad?

Step-by-step explanation:

let x= time period in years between age now and when  father's age=2* the samad's age

in x years father's age will be 40 + x years old

in x years samad's age will be 12+x years old

at a certain point in time, the father's age = 2*the samad's age

40+x=2*(12+x)

or, 40 +x=24 + 2x

or, 40-24 = x

   x=16

test:

father=40+16=56

son=12+16=28

hence , after 16 years samad's father will be twice as old as samad

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

answer: asdfghjkl,mnbv

step-by-step explanation: