Using coordinates of the labeled points to find a point slope equation of the line

y +4= -3 ( x-3)

Step-by-step explanation:

The point slope form of a line is

y-y1 = m(x-x1)

The point requested is (3,-4)

y - -4= m ( x-3)

y +4= m ( x-3)

The slope of the line  is positive since it goes from the top left to the bottom right

The slope can be found from (0,5) and (3,-4)

m = (y2-y1)/(x2-x1)

    = (5 - -4)/(0-3)

    = (5+4)/(0-3)

    = 9/-3

    = -3

y +4= -3 ( x-3)

The slope in all answer choices is 3 or -3.

Since the line is going down, the slope is going to be negative (-3).

Point slope form: y - y1 = m(x - x2)

We are given a point in the question so use it to fill in the equation.

y + 4 = -3(x - 3)

Best of Luck!

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.

time is equal to distance over rate so

t = d/r

need a little bit more information for the second question.