I NEED HELP PLEASE ASAP! :) A 2600-pound truck is stopped at a red light on a hill with an incline of 25°. Ignoring the force of friction, what force is required to keep the truck from rolling down the hill? (Show work)

( About ) 1,099 pounds

Step-by-step explanation:

The force required to keep this truck from rolling down the hill is opposed by the force of friction, comparative to the 2600 pounds of force against this friction. It should be that this opposing force is at work more towards the bottom of this hill, and thus the question asks the magnitude of latter force to keep this truck idle -

|| F || = sin( 25 ) * ( Fg ) = sin( 25 ) * ( 2600 lb ) = ( About ) 1098.80748 pounds

This can be rounded to a solution of 1099 pounds

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.

from the figure we get,

the x axis shows   the months and,

the y-axis shows the number of satisfied customer.

each line or each cell in upward direction (y-axis) shows 500.

the appropriate scale for the y - axis is: -

a = 2000 customers

b = 4000 customers

c = 6000 customers

d = 8000 customers

e = 10000 customers

f = 12000 customers

g = 14000 customers