[40 points] QUICKLY PLEEEASE :) Which sequence of transformations could be used to map triangle MNO onto M”N”O”? T(–2, 4) ry-axis ry-axisT(–2, 4) T(2, –4) T(2, –4)

Therefore, the correct option is;

T(-2, 4) ry-axis

Step-by-step explanation:

Given that the points of the triangle MNO are N(3, -2), O(1, -3), and M(5, -4), while M''(-3, 0), N''(-1, 2), and O''(1, 1), we have;

N(3, -2) → N''(-1, 2)

For reflection about the y-axis, the y values are the same and the x values change sign

If we translate by (-2, 4) we have;

N(3, -2) → N'(3 - 2, -2 + 4) = N'(1, 2)

If we now reflect about the y-axis, we have;

N'(1, 2), reflection → N''(-1, 2) which is correct

For O(1, -3), O''(1, 1), we have;

O(1, -3) → O'(1 - 2, -3 + 4) = O'(-1, 1)

Reflecting about the y-axis gives;

O'(-1, 1) → O''(1, 1) correct

For M(5, -4) M''(-3, 0)

M(5, -4) → M'(5 - 2, -4 + 4) = M'(3, 0)

M'(3, 0) → M''(-3, 0)

Therefore, the correct option is T(-2, 4) ry-axis.

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.