Determine the strongest classification for quadrilateral ABCD with vertices at A(1, 2), B(3, 5), C(5, 3), and D(2, 1).

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)

150.6

all i did was i multiplied 5.02 by 30

19479 is the answer ^^

answer: x=1

step-by-step explanation:

f(x) = g(x)

x - 2 = -1

x = 1

therefore the graph should be a line showing x=1 which is vertical and passes on 1

hope it !