What are the solutions to the nonlinear system of equations below?
Check all that apply.

Option C and Option F are the right options.

solution,

Now

When X=4,

When X=-4,

The solutions are (4,0) and (-4,0)

Hope this helps...

good luck on your assignment..

C and F

Step-by-step explanation:

x² + y² = 16  ------------------(I)

x² - y² = 16 ---------------(I)

(I)                x² + y² = 16

(I)               x² - y² = 16    {add & y² will be eliminated}

                 2x²     = 32

x² = 32/2

x² = 16

x = √16

x = ±4

When x = 4,

4² + y² = 16

16 + y² = 16

      y² = 16 - 16

      y² = 0

y = 0

(4,0) is a solution

When x = -4,

(-4)² + y² = 16

16 + y² = 16

      y² = 16 - 16

      y² = 0

y = 0

(-4, 0 ) is a solution

x= -3

step-by-step explanation:

step 1: simplify brackets

4 - x - 1 = 6

step 2: simpilfy

3 - x = 6

step 3: subtract 3 from both sides

-x = 6 - 3

step 4: simpilfy 6 - 3

-x = 3

step 5: multiply both sides by -1

x = -3