Help! I'm trying to solve this for A and B, and it keeps telling me I'm wrong. The equation is: √x(7x-4√x)=Ax^(3/2) + Bx
Where A =
and B =

A must be 7 and B must be -4

Step-by-step explanation:

Perform the indicated multiplication, obtaining:

7x^(3/2) - 4x  =  Ax^(3/2) + Bx

Then A must be 7 and B must be -4

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

welcome!

step-by-step explanation:

no, her answer is not correct.   we square the lengths of all sides and then determine whether the pythagorean theorem holds here:

9² + 15² = 306.   this is not equal to the square of the longest side ( that square being 395.   answer c is correct.