HELP PLEASE The annual salaries of all employees at a financial company are normally distributed with a mean Mu = $34,000 and a standard deviation Sigma = $4,000. What is the z-score of a company employee who makes an annual salary of $28,000 A. -5 B. -3.5 C. -1.5 D.1.5

C

Step-by-step explanation:

In this question, we are interested in calculating the z-score of a company employee.

Mathematically;

z-score = (x- mean)/SD

where in this case;

x is the value given which turns out to be the annual salary of the employee = 28,000

Mean = 34,000

standard deviation = 4,000

Plugging these values into the equation above, we have;

z-score = (28000-34000)/4000 = -6000/4000 = -1.5

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

answer: 88

step-by-step explanation: