Two urns both contain green balls and red balls. Urn I contains 4 green balls and 8 red balls and Urn II contains 2 green balls and 5 red balls. A ball is drawn from each urn. What is the probability that both balls are red? a. 10/21 b. 2/21 c. 5/21 d. 5/84 Please select the best answer from the choices provided A B C D

10/21

Step-by-step explanation:

From the question, we are told that two urns both contain green balls and red balls. Urn I contains 4 green balls and 8 red balls and Urn II contains 2 green balls and 5 red balls.

Urn 1 contains 4 green balls and 8 red balls. This means that the probability of drawing a red ball in urn 1 will be 8/12 = 2/3.

Urn II contains 2 green balls and 5 red balls. This means that the probability of drawing a red ball in urn 2 will be 5/7

Since we've the probability of drawing a red ball from both urns, we then multiply them together. This will be:

= 2/3 × 5/7

= 10/21

what do u need to know

step-by-step explanation:

i believe it is b and c. (side note, i got the same computer from k-12 lol i’m in 8th grade and this is my first year, will it get

step-by-step explanation: