Mathematics, 14.07.2020 18:01 harleyquinn1241

What is the nth term rule of the quadratic sequence below? 4,15,30,49,72,99,130,...

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Answer from: rtorres3

The nth term rule of the quadratic sequence is $2n^{2} +5n-3$ .

Step-by-step explanation:

We are given the following quadratic sequence below;

4, 15, 30, 49, 72, 99, 130,...

As we know that the formula for the nth term of the quadratic sequence is given by = $an^{2}+bn+c$

Firstly, we will find the difference between the term of the given sequence;

1st difference of the given sequence;

(2nd term - 1st term), (3rd term - 2nd term), (4th term - 3rd term), (5th term - 4th term), (6th term - 5th term), (7th term - 6th term)

= (15 - 4), (30 - 15), (49 - 30), (72 - 49), (99 - 72), (130 - 99),....

= (11, 15, 19, 23, 27, 31,.....)

Now, we will find the second difference of the given sequence, i.e;

= (15 - 11), (19 - 15), (23 - 19), (27 - 23), (31 - 27),....

= (4, 4, 4, 4, 4)

Since the differences are same now, so to find the value of a we have to divide the value of second difference by 2, i.e;

The value of a = $\dfrac{4}{2}$ = 2

SO, the first term of the nth term rule equation is $an^{2}$ = $2n^{2}$ .

Now, in the term $2n^{2}$ , put the value of n = 1, 2, 3, 4 and 5 and then form the sequence, i.e;

If n = 1, then $2n^{2}$ = $2 \times (1)^{2}$ = 2

If n = 2, then $2n^{2}$ = $2 \times (2)^{2}$ = 8

If n = 3, then $2n^{2}$ = $2 \times (3)^{2}$ = 18

If n = 4, then $2n^{2}$ = $2 \times (4)^{2}$ = 32

If n = 5, then $2n^{2}$ = $2 \times (5)^{2}$ = 50

SO, the sequence formed is (2, 8, 18, 32, 50).

Now, find the difference of this sequence and the original quadratic sequence, i.e;

= (4 - 2), (15 - 8), (30 - 18), (49 - 32), (72 - 50)

= (2, 7, 12, 17, 22)

Now, as we can see that the above sequence resembles the general form of (5n - 3) because:

If we put n = 1, then (5n - 3) = 5 - 3 = 2

If we put n = 2, then (5n - 3) = 10 - 3 = 7 and so on....

From this, we concluded that the value of b and c are 5 and (-3) respectively.

Hence, the nth term rule for the given quadratic sequence is $2n^{2} +5n-3$ .

Answer from: Quest

ans789

step-by-step explanation:

Answer from: Quest

First step is to get rid of the square root. remember that a square root is the same as raising to the (1/2) power. see below: $\sqrt{\frac{ {72x}^{16} }{ {50x}^{{{36} }}}} = \frac{ { \sqrt{72}x}^{ {16}^{ (\frac{1}{2}) } } }{ { \sqrt{50} x}^ {{36}^{ (\frac{1}{2}) } }}$ multiply exponents per exponent rules to get: $\frac{ { \sqrt{72}x}^{8} }{ { \sqrt{50}x}^{18} }$ remember you subtract exponents from the denominator and add exponents in the numerator so: $\sqrt{ \frac{72}{ 50}} \times ( {x}^{(8 - 18) } ) = \sqrt{ \frac{36}{25} } \times ( {x}^{ - 10} )$ simplify further: $\frac{6}{5} {x}^{ - 10} = \frac{6}{5 {x}^{10} }$ so a is the correct choice. if you don't understand this google exponent rules and it will you understand. look at the image results.
Plz hurrywhat is the simplified form of ? assume x ≠ 0.

Plz hurrywhat is the simplified form of  ? assume  x  ≠ 0.

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What is the nth term rule of the quadratic sequence below? 4,15,30,49,72,99,130,......

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