The function h(t) = 2.3 + 50t - 1.86t^2 models the height of an arrow shot from a bow on Mars, where h(t) is the height in metres and t is time in seconds. How long does the arrow stay in flight?

The arrow stay in flight for 26.92 seconds

Step-by-step explanation:

We are given that  the height of an arrow shot from a bow on Mars is modeled by equation:

Where h(t) is the height of arrow

t is the time in seconds

Now we are supposed to find How long does the arrow stay in flight?

Substitute h(t)=0

So,

t=-.04 , 26.92

Since the time cannot be negative

So,the arrow stay in flight for 26.92 seconds

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq

7

step-by-step explanation:

i'm assuming you need to figure out how many campers go into each tent.

i got the answer by:

24+4=28

28/4=7