subject
Mathematics, 13.07.2020 17:01 justritegrl

For a study regarding mean cadence, two-way ANOVA was used. The two factors were walking device (none, standard walker, rolling walker) and dual task (being required to respond vocally to a signal or no dual task required). Results of two-way ANOVA showed that there was no evidence of interaction between the factors. However, according to the article, "the ANOVA conducted on the cadence data revealed a main effect of walking device." When the hypothesis regarding no difference in mean cadence according to which, if any, walking device was used, the sample F was 30.94, with d. f.N = 2 and d. f.D = 18. Further, the P-value for the result was reported to be less than 0.05. Required:

What is the conclusion regarding any difference in mean cadence according to the factor "walking device used"?

ansver
Answers: 2

Another question on Mathematics

question
Mathematics, 21.06.2019 16:30
What could explain what happened when the time was equal to 120 minutes
Answers: 2
question
Mathematics, 21.06.2019 16:50
1. the wheeling bridge in west virginia is about 307 meters long. if you walk with a stride of about meter, about how many steps would it take you to cross this suspension bridge?
Answers: 1
question
Mathematics, 21.06.2019 18:30
How far could you drive on 50 gallons of gas
Answers: 2
question
Mathematics, 21.06.2019 21:00
In the field of thermodynamics, rankine is the unit used to measure temperature. one can convert temperature from celsius into rankine using the formula , what is the temperature in celsius corresponding to r degrees rankine? a. 9/5(c - 273) b. 9/5(c + 273) c. 5/9( c - 273) d. 5/9( c + 273)
Answers: 1
You know the right answer?
For a study regarding mean cadence, two-way ANOVA was used. The two factors were walking device (non...
Questions
question
Mathematics, 01.12.2020 01:00
question
Computers and Technology, 01.12.2020 01:00