What are the solutions of the equation x^4 + 6x^2 + 5 = 0? Use u substitution to solve.

second option

Step-by-step explanation:

Given

+ 6x² + 5 = 0

let u = x², then

u² + 6u + 5 = 0 ← in standard form

(u + 1)(u + 5) = 0 ← in factored form

Equate each factor to zero and solve for u

u + 1 = 0 ⇒ u = - 1

u + 5 = 0 ⇒ u = - 5

Change u back into terms of x, that is

x² = - 1 ( take the square root of both sides )

x = ± = ± i ( noting that = i ), and

x² = - 5 ( take the square root of both sides )

x = ± = ± = ± × = ± i

Solutions are x = ± i and x = ± i

answer is 144

step-by-step explanation:

its 60

4 x 12 = 48

3 x 4 = 12

48 + 12 = 60

yeeeet