The vertex form of a function is g(x) = (x - 3)2 + 9. How does the graph of g(x) compare to the graph of the function f(x) = x2?
g(x) is shifted 3 units left and 9 units up.
g(x) is shifted 3 units right and 9 units up.
O g(x) is shifted 9 units left and 3 units down.
g(x) is shifted 9 units right and 3 units down.
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i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3

i believe the answer is c.