This is a cross-sectional view of candy bar ABC. A candy company wants to create a cylindrical container for candy bar ABC so that it is circumscribed about the candy bar. If segment AD = 4 cm, what is the smallest diameter of wrapper that will fit the candy bar? Triangle ABC in which point E is between points A and B, point D is between points A and C, point F is between points B and C, segments AE and EB are congruent, segments BF and FC are congruent, and angles AED, ABF, and DFC are right angles.

8 cm

Step-by-step explanation:

When a right triangle is circumscribed in a circle, the diameter is the hypotenuse AC.

Therefore, the smallest diameter of the wrapper will be that of the circle whose diameter has endpoints of A and C.

From the diagram:

Therefore, Triangle AED is congruent to Triangle DFC and in fact AD=DC.

Given: AD =4 cm

Therefore, the smallest diameter

AC=AD+DC

=4+4

=8 cm

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above