Hi:) how to do this?

b) 15.2km

c) Bearing= 263.8° (1 d.p.),

AD= 25.5 km (3 s.f.)

Step-by-step explanation:

Please see attached picture for full solution.

In picture 3, you could also use trigonometry to find AW, just like how we did to find W.

Picture 4:

WD= 16 -15.250

WD= 0.75

Picture 5:

Bearing of D from A

= reflex ∠N₂AD

= 295° - ∠BAD

∠BAD

= ∠BAW -∠WAD

= 33° -1.829°

= 31.171°

Thus, bearing of D from A

= 295° - 31.171°

= 263.8° (1 d.p.)

c) Distance of D from A= length AD

Look at triangle BAD:

∠DBA= 65°

∠ADB= 180° -65° -31.171° (∠ sum of △ADB)

∠ADB= 83.829°

Using sine rule,

Feel free to ask if you have any queries :)

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq

x/3-10=8

x/3=18

x=48