Find the area of the image below .

a.41 square units.
b.44 square units.
c.52 square units.
d.56 square units

The answer is: A. 41 square units. Let point F be (6,5). The total area (A0) is the sum of the area (A1) of the right triangle A B F and the area (A2) of the square C D E F: A0 = A1 + A2. The area of the right triangle A B F is: A1 = (B F * A F)/2. From the image: B F = 10 units and A F = 5 units. So: A1 = (10 * 5)/2 = 50/2 = 25 square units. The area of the square is: A2 = C D * D E. From the image: C D = D E = E F = F C = 4 units. So: A2 = 4^2 = 16 units. From here, the total area is: A0 = A1 + A2 = 25 + 16 = 41 square units.

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