Find the value of B - A if the graph of Ax + By = 3 passes through the point (-7, 2), and is parallel to the graph x + 3y = -5. Pls help ASAP btw, the answer isn’t -12/19 or 12/19

Step-by-step explanation:

Given

Point: (-7,2)

x + 3y = -5

Required

Find B- - A in Ax + By = 3

To start with; we need to calculate the slope of x + 3y = -5

Subtract x from both sides

Divide both sides by 3

The slope of the line is the coefficient of x

Slope =

The question says line Ax + By = 3 is parallel to line x + 3y = -5; This means that they have the same slope of

Having calculated the slope, next is to calculate the equation of the line using the following formula;

Where m is the slope; m = ;

Substitute these values in the formula above; the formula becomes

Cross Multiply

Open brackets

Add x to both sides

Add 6 to both sides

Multipby both sides by -3

Comparing the above to Ax + By = 3

the 4th choice is the correct one

step-by-step explanation:

hello,

as we don't know if g(x) is continue,

answer b

f(x)=2x²-8x+1=2(x²-4x+4)+1-8=2(x-2)²-7

vertex is (2,-7) ( a minimum since coefficient of x² is > 0)