Determine whether the given signal is a solution to the difference equation. Then find the general solution to the difference equation. y_k = k^2: y_k + 2 + 8y_k + 1 - 9y_k = 20k + 12 the given signal is a solution to the difference equation? No Yes What is the general solution to the difference equation? y_k = 20k + 12 + c_1 k^2 + c_2(-9)^k y_k = k^2 + c_1(-9)^k + c_2 y_k = 20k + 12 + c_1(-9)^k + c_2 Since y_k = k^2 is not a particular solution, there is not enough information to determine the general solution.

The answer to this question can be defined as follows:

Step-by-step explanation:

The given equation is:

put,

hence y_k=k^2 is its solution.

Now,

the symbol form is:

The general solution is:

The complete solution is:

The answer is option b:

After solve the complete solution is:

p = 6s

step-by-step explanation:

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)