If h(x) = 5 + x and f(x) = 5, which expression is equivalent to (kn)(x)?

Step-by-step explanation:

The question is not correctly written, here is the correct question.

If h(x) = 5 + x and k(x) = 5, which expression is equivalent to (koh)(x)?

(koh)(x) can be rewritten as k{h(x)}

Since h(x) = 5+x then,  k{h(x)} = k(5+x)

Note that k(x) can be written as 5x°

k(5+x) = 5(5+x)°

Since any value raise to the power of zero is 1, then;

k(5+x) = 5(1)

k(5+x) = 5

(koh)(x) =  k{h(x)}  = 5

For (hok)x;

(hok)x = h{k(x)}

= h(5)

= h(5x°)

Since h(x) = 5+x

h(5x°) = 5+5x°

h(5x°)= 5+5 = 10

(hok)x = h(k(x)) = 10

c

step-by-step explanation:

it would be see because your formula is f(x)=6x, so 6 times 1 is 6 and you go on and the best answer is c.