A figure is located at (2, 0), (2, −2), (6, −2), and (6, 0) on a coordinate plane. What kind of 3-D shape would be created if the figure was rotated around the x-axis? Provide an explanation and proof of your answer to receive full credit. Include the dimensions of the 3-D shape in your explanation.

Step-by-step explanation:

After doing this we notice that the shape we get a rectangle.But noticing isn't enough we should prove it mathematically :

how ?

This will make the task easier.

[AB] ⊥ [BD] ⇒ VECTOR AB .VECTOR BC = NULL VECTOR

Now V(AB) . V(BC) = (6-2)*(6-6)+(0-0)(-2-0)

                                  = 0-0

                                   = NULL VECTOR

[AD] ⊥ [DC]  ⇒ VECTOR AD .VECTOR DC = NULL VECTOR

Now V(AD) . V(DC) = (2-2)*(6-2)+(-2+2)*(2-0)

                                 =  0-0

                                 = NULL VECTOR

Let r be the radius of the cylinder's base and h its height.

answer: c

step-by-step explanation: because you don't have to draw a point of intersection. couldyou give me brainliest?

u

what? ?

what type of question is thiss

step-by-step explanation: