Mr. Brown has $185 in his wallet consisting of only $5 bills and $10 bills. If there are 28 bills in his wallet, how many of each type are there?

9 bills of $10 and 19 bills of $5

Step-by-step explanation:

Mr. Brown has $185 of which he has $10 bills and $5 bills. He has total 28 bills in his wallet all of which can be either $10 bill or $5 bill. The numbers of $10 bills are 9 bills and 19 bills of $5 bills. The total will be 28 bills (9 bills + 19 bills).  The total amount will be $185 [(9 bills *$5) + (19 bills of $10)].

your answer is 23/2 - 13.5

step-by-step explanation:

7/2 evaluates to

multiply x and 4.5

multiply x and 1

the x just gets copied along.

the answer is x

x

4.5*x evaluates to 4.5x

multiply 3 and 4.5x

multiply 1 and x

the x just gets copied along.

x

4.5*x*3 evaluates to 13.5x

7/2-4.5*x*3 evaluates to

  + 8 =

the answer is

7/2-4.5*x*3+8 evaluates to