If sin(yº) = cos(xº), which of the following statements is true?

y=90-x=w

thus x=z and mB = mD =90

and ∆ABC ~ ∆CDE

Option 3

Step-by-step explanation:

sin y= BC/AC

cos x= DE/CE

⇒ DE≅BC, DC≅AB, ∠w=∠y, ∠x=∠z

⇒ ΔABC≅CDE

Option 3 is correct

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

this is not the answer this is just a question. is this middle school math?

step-by-step explanation: