Find the values of a and b such that x^2+2x+2=(x-a)^2+b

a = -1

b = 1

Step-by-step explanation:

Step 1: Isolate x's

x² + 2x = -2

Step 2: Complete the Square

x² + 2x + 1 = -2 + 1

(x + 1)² = -1

Step 3: Move everything to 1 side

(x + 1)² + 1 = 0

And we have our answer.

step-by-step explanation:

no, her answer is not correct.   we square the lengths of all sides and then determine whether the pythagorean theorem holds here:

9² + 15² = 306.   this is not equal to the square of the longest side ( that square being 395.   answer c is correct.