What is the equation of the parabola with vertex (-2,5) and an x-intercept of x = 3

Step-by-step explanation:

if parabola has a vertex not in x-axis, it should have 2 x intercept

x-vertex = -2

first x intercept = 3

second x intercept should -7

so the equation will like this

y = a(x-x1)(x-x2)

y = a (x-3)(x+7)

y = a(x² + 4x - 21)

5 = a((-2)² + 4(-2) - 21)

5 = a(4 - 8 - 21)

5 = a(-25)

a = 5/(-25)

a = -1/5

then the equation is

y = (-1/5)(x² - 4x - 21)

or you can write as

y = -x²/5 + 4x/5 + 21/5

or as this one

5y = -x² + 4x + 21

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068