Find the amount in an account where $500 in invested at 2.5% compounded quarterly for a period of 10 years.

The amount in an account where $500 in invested at 2.5% is $641.51.

Using this formula

A = p (1+ r/n)^nt

Where:

A=Amount

P= Principal=$500

R=Rate=2.5% or 0.025

n=4 (Quarterly)

T=Time=10 years

Let pug in the formula

A = $500(1 + 0.025/4)^4×10

A=$500(1.28302)

A =$641.51

Inconclusion the amount in an account where $500 in invested at 2.5% is $641.51.

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$641.51

Step-by-step explanation:

A = p (1+ r/n)^nt

A = 500 (1 + 0.025/4)^4*10

A = 641.51

"if it is my birthday, then it is snowing"

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet