A square fits exactly inside a circle with each of its vertices being on the circumference of the circle.
The square has sides of length xcm.
The area of the circle is 56 cm?.
Work out the value of x.
Give your answer correct to 3 significant figures.

5.97

Step-by-step explanation:

If the radius of the circle = r then

pi r^2 = 56

r^2 = 56/pi

r = sqrt(56/pi)

The radius of the circle is equal to half of a diagonal of the square. That is,

r = (1/2) sqrt (2x^2)

= x (sqrt 2)/2

= x/(sqrt 2)

So x = r sqrt 2

= sqrt (56/pi) sqrt 2

= 4 sqrt (7/pi)

= 5.9708

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

21.4 i did it already for s1

step-by-step explanation: