In a certain liberal arts college with about 10,000 students, 59% are males. If two students from this college are selected at random, what is the probability that they are of the same gender?

P(S) = 0.5162 or 51.62%

the probability that they are of the same gender is 0.5162 or 51.62%

Step-by-step explanation:

The probability that the two selected students are of the same gender P(S) is;

P(S) = Probability that they are both male P(M) + probability that they are both female P(F)

P(S) = P(M) + P(F) 1

Given;

Proportion of male = 59% = 0.59

Proportion of female = 1-0.59 = 0.41

P(M) = 0.59×0.59 = 0.3481

P(F) = 0.41 × 0.41 = 0.1681

From equation 1;

P(S) = 0.3481 + 0.1681

P(S) = 0.5162 or 51.62%

the probability that they are of the same gender is 0.5162 or 51.62%

is this a multiple choice question?

if so it's a and c

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!