The ratio of money in Obi's wallet to Rudy's wallet one day was 5:2. Obi spent £20 that day. Obi now had £8 less than Rudy. How much did they have initially altogether?

Initially, they have £28 altogether

Step-by-step explanation:

Obi: Rudy=5:2

this means that Obi had 5x and Rudy has 2x in their wallets.

Obi spent £20 and 5x-20 left. Obi now had £8 less than Rudy

thus,

2x-(5x-20) =8

2x-5x+20=8

-3x=-12

x=4

obi =5x

=5*4

=20

Rudy =2x

=2*4

=8

This means that initially Obi had £20 and Rudy had £8

Total if Rudy and obi

=£8+£20

=£28

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

wait nvm i know the correct answer now its 100%   81 square feet

~batmans wife dun dun