Two mechanics worked on a car. The first mechanic worked for 20 hours, and the second mechanic worked for 15 hours. Together they charged a total of $3275. What was the rate charged per hour by each mechanic if the sum of the two rates was $180 per hour?

The rate charged per hour by each mechanic are $115 per hour and $65 per hour

Step-by-step explanation:

Let x be the rate charged per hour by first mechanic

Let y be the rate charged per hour by second mechanic

Cost for first worker working for 20 hours = 20x

Cost for second worker working for 15 hours = 15y

We are given that . Together they charged a total of $3275.

So, 20x+15y=3275  1

We are also given that the sum of the two rates was $180 per hour

So, x+y=180   2

Substitute the value of x form 2 in 1

20(180-y)+15y=3275

y=65

Substitute the value of y in 2

x+65=180

x=180-65

x=115

Hence the rate charged per hour by each mechanic are $115 per hour and $65 per hour

the forst and 3rd

step-by-step explanation:

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.