A factory purchased 15 machines. Each machine has 0.2 probability of breaking down. What is the probability of 1 machine breaking down?

The probability of one machine breaking down

P(X=1) = 0.13194

Step-by-step explanation:

Step(i):-

Given sample size 'n' = 15

The probability of breaking down of each machine = 0.2

p = 0.2

q = 1-p = 1-0.2 = 0.8

Step(ii)

Let 'X' be the random variable in binomial distribution

The probability of one machine breaking down

On calculation , we get

P(X=1) = 15 ×(0.2)×(0.8)¹⁴

P(X=1) = 0.13194

Final answer:-

The probability of one machine breaking down

P(X=1) = 0.13194

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x