Evaluate 32 + (4c − 6c) + (2 + 6c) for c = 5. A.22 B.64 C.−10 D.54

The answer is option D

32 + (4c − 6c) + (2 + 6c)

c = 5

32 + ( 4(5) - 6(5)) + (2 + 6 (5)

= 32 + (20 - 30) + ( 2 + 30)

= 32 - 10 + 32

= 54

Hope this helps

D. 54

Step-by-step explanation:

32 + (4c - 6c) + (2 + 6c)

Put c as 5 and evaluate.

32 + 4(5) - 6(5) + 2 + 6(5)

Multiply the terms.

32 + 20 - 30 + 2 + 30

Add or subtract the terms.

32 - 10 + 2 + 30

22 + 32

= 54

the answer is a if my teacher taught me correct