Question # 2: Find the probability distribution of the number of boys in families with three children, assuming equal probabilities for boys and girls.

 P(3 boys)=1/8

P(1 boy)=3/8

P(2 boys)=3/8

P(0 boys)=1/8

Step-by-step explanation:

Lets use letter B-for the boys and letter G for the girls

Lets use for any situation  description  3 simbols.

For example GBG - mens 1st kid is girl, second is boy and the third one is girl again

We have only 1 set of 3 BOYS :   B-B-B  -TOTAL 1 set

The sets of 2 BOYS are looking as follows:  B-B-G, B-G-B, G-B-B - TOTAL 3 sets

The sets of 1 BOY are looking as follows:  B-G-G, G-B-G, G-G-B - TOTAL 3 sets

Finally we have only 1 set of 0 BOYS :   G-G-G  -TOTAL 1 set

Total amount of sets is 8.

So probability of 3 boysamong 3 kids is P(3 BOYS)=1/8

probability of 2 boys among 3 kids is P(2 BOY)=3/8

probability of 1 boy among 3 kids is P(1 BOY)=3/8

probability of 0 boy among 3 kids is P(1 BOY)=1/8

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11