If p and q are the roots of the equation
3x - 16x + 2 = 0, find the value of
p+(1+p).

To find p and q which are the roots we must first solve the quadratic equation above.

3x² - 16x + 2 = 0

Using the quadratic formula

x = - b ± √b² - 4ac / 2a

where a = 3 b = -16 c = 2

Substitute the above values into the formula

x = --16±√(-16)² - 4(3)(2)/2(3)

x = 16±√ 256 - 24 / 6

x = 16± √ 232/6

After solving

x = 8 + √58 / 3 or x = 8 - √58 / 3

Therefore p = 8 + √58 / 3 and

q = 8 - √58 / 3

So p + ( 1 + p) is

= 8 + √58 / 3 + ( 1 + 8+√58 / 3)

= 19 + 2√58/3 or 11.41

Hope this helps.

sine

step-by-step explanation:

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632