I NEED HELP NOW PLS ASAP

Step-by-step explanation:

hello,

I understand that there are only 4 cards  and then the player draw a card out of the 4 cards, replace it so the second draw is still out of the 4 cards

How many ways can you draw two cards?

as the first card is replaced, this is 4*4=16

so there is 16 possibles ways

hearts hearts

hearts clubs

hearts diamonds

hearts spades

clubs hearts

clubs clubs

clubs diamonds

clubs spades

diamonds hearts

diamonds clubs

diamonds diamonds

diamonds spades

spades hearts

spades clubs

spades diamonds

spades spades

out of these 16 ways, how many have same colour for both cards?

I assume that there are only two colours Red and Black, so we can have

only 8 ways so the first probability is 8/16 = 1/2

out of these 16 ways, how many are red ace first and black ace?

There are 4 ways so the probability is 4/16 = 1/4

hope this helps

Standard deck has aces in four colors

Player draws one from four so the probability of drawing any first card is 1/4 (in the first drawing)

We replace the card so in second drowing its the same

So the probability of drawing two card of one chosen color is 1/4*1/4, and we have four colors

The probability of drawing two card of the same color is:

There are 2 red aces and 2 black aces

(sorry for coments - not reading carefully)

So a probability of drawing red ace in first drawing is 2/4=1/2

a probability of drawing black ace in second drowing is the same ('cause we replace the one drawn first)

So the probability that a red ace is drawn first and then the black ace is:

-4

step-by-step explanation:

(-4+8)=-(4-8)=-8+4=-4