In an examination, Ram obtained 12 marks less than shyam. If he had obtain half as many marks again as he did, he would have beaten shyam by 11 marks. Find the marks obtained by each?

Shyam's mark: 58

Ram's mark: 46

Step-by-step explanation:

r = s - 12 (r is for Ram and s is for Shyam) for this example:

(1/2)(r - 12) = s + 11

This is because Shyam would have beaten by 11 marks.

(r - 12) + (1/2)(r - 12) = s + 11

2(r - 12) + (r - 12) = 2(s + 11)

2r - 24 + r - 12 = 2s + 22

r = 22 + 24 + 12

s = 58

r = 58 -12 = 46

Hope this helps!

take it another

cosine

step-by-step explanation: