Natalia wants to attend Louisiana State University. One year at Louisiana State University costs approximately $24,000. She currently has $4,000 in savings. Natalia has received a one-time grant of $1,500 and an annual academic scholarship for $3,500. She plans to enroll in the work study program that will pay $12,000 annually for part-time work. How much will Natalia need to borrow in student loans in order to attend Louisiana State University for 4 years?

He needs to borrow $28,500 to attend the University for 4 years.

Step-by-step explanation:

One year at the University costs $24,000. The total she has to pay are 4 * $24,000 = $96,000

minus the $4,000 she has in savings: $96,000 - $4,000 = $92,000

minus the $1,500 she received one time: $92,000 - $1,500 = $90,500

minus $3,500 per anual

           4* $3,500 = $14,000            

           $90,500 - $14,000 = $76,500

minus $ 12,000 per anual

            4 * $12,000 = $48,000

            $76,500 - $48,00 = $28,500

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

how many players are there?

step-by-step explanation: