Seven new employees, two of whom are married to each other, are to be assigned seven desks that are lined up in a row. If the assignment of employees to desks is made randomly, what is the probability that the married couple will have adjacent desks

2/7

Step-by-step explanation:

Seven employees can be arranged in 7! ways. n(S) = 7!

Two adjacent desks for married couple can be selected in 6 ways viz.,(1, 2), (2, 3), (3,4), (4, 5), (5,6),(6,7).

This couple can be arranged in the two desks in 2! ways. Other five persons can be arranged in 5! ways.

So, number of ways in which married couple occupy adjacent desks

= 6×2! x 5! =2×6!

so, the probability that the married couple will have adjacent desks

c. (0.6,-1.4)

step-by-step explanation:

hope this

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]