The length of time it takes to find a parking space at 9 A. M. follows a normal distribution with a mean of 6 minutes and a standard deviation of 3 minutes. Eighty percent of the time, it takes more than how many minutes to find a parking space

And if we solve for a we got

Eighty percent of the time, it takes more than 8.526 how many minutes to find a parking space

Step-by-step explanation:

Let X the random variable that represent the lenght of time it takes to find a parking space of a population, and for this case we know the distribution for X is given by:

Where and

For this part we want to find a value a, such that we satisfy this condition:

  (a)

  (b)

We want to find a value who accumulate 0.80 of the area on the left and 0.2 of the area on the right it's z=0.842.

If we use condition (b) from previous we have this:

Using this formula we have:

And if we solve for a we got

Eighty percent of the time, it takes more than 8.526 how many minutes to find a parking space

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2

dilation scale factor 2: starting with δabc, draw the dilation image of the triangle with a center at the origin and a scale factor of two. notice that every coordinate of the original triangle has been multiplied by the scale factor (x2). dilation with scale factor 2, multiply by 2.