If Machine A makes a yo-yo every five minutes and Machine B takes ten minutes. How many hours would it take them to make 20yo−yos? Give me the hours and minutes. WILL GIVE BRAINLIEST

Time in minutes = 66 2/3

Time in hours = 1.11

Step-by-step explanation:

Problem:

Time taken by both machine to make 20  yo-yo

let the time taken be x minutes

Given

Time taken by machine A  to make 1 yo-yo = 5 mins

No. of yo-yo made by machine A in x minutes = x/5

Time taken by machine B  to make 1 yo-yo = 10 mins

No. of yo-yo made by machine B in x minutes = x/10

Total no. of yo-yo made by both the machine = x/5 + x/10 = (2*x+x)/10

Total no. of yo-yo made by both the machine = 3x/10

But given that together they made 20 yo -yo

Thus,

3x/10 = 20

=> x = 20*10/3 = 200/3

Thus, it took 66 2/3 minutes to make 20 yo-yo by both of them

In one hour there is 60 minutes

Time taken in Hours will be = 200/3*60 = 200/180 = 10/9 = 1 1/9= 1.11 hours

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )