The equation of line CD is y = −2x − 2. What is the equation of a line parallel to line CD in slope-intercept form that contains point (4, 5)? y = −2x + 13
y = negative one halfx + 7
y = negative one halfx + 3
y = −2x − 3

y = −2x + 13

Step-by-step explanation:

equation of line slope intercept form is y = mx +c

where m is slope and c is y intercept

when two lines are parallel then their slope are equal.

Given line

CD

y = −2x − 2

it is in form of y = mx +c

thus, m = -2

Given that other line parallel to CD  y = −2x − 2

Thus, its slope will be -2.

Let the equation of required line be

y = mx +c (as slope will be -2)

Then equation of line will be

y = -2x +c

Given that this line contains (4,5) it will satisfy the equation y = -2x+c

using x = 4 and y = 5

we have

y = -2x +c

5 = -2*4 + c

=> 5 = -8 + c

=> c = 5+8 = 13

Thus, equation of line parallel to  y = −2x − 2 and containing point(4,5) is

y = −2x + 13

the answer is 31.27mph