Which equation correctly uses the law of cosines to solve for the length s?
92 = 52 + 102 - 2(s)(10) cos(100°)
9 = s + 10 - 2(s)(10)cos(100)
102 = 52 + 100 – 2(s)(10)cos(100)
S2 = 92 + 102 - 2(9)(10)cos(100)

fourth option

Step-by-step explanation:

Using the Law of Cosines in Δ STU to find s

s² = t² + u² - 2us cosS

where t = 9, u = 10 and S = 100° , thus

s² = 9² + 10² - 2(9)(10)cos100°

answer: the answer is simply nothing.

step-by-step explanation: because there is no ending to this question

gimme brainliest > : 3

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204